% Aufgabe 23-3, Aufgabenstellung b:
A = [5.6308 -4.6386 1.2155 0 0 0 0
-4.6386 7.3013 -5.1020 1.3355 0 0 0
1.2155 -5.1020 8.0215 -5.5991 1.4641 0 0
0 1.3355 -5.5991 8.7937 -6.1318 1.6018 0
0 0 1.4641 -6.1318 9.6203 -6.7016 1.7490
0 0 0 1.6018 -6.7016 10.5040 -7.3103
0 0 0 0 1.7490 -7.3103 9.3735] ;
B = [2 -1 0 0 0 0 0 ;
-1 2 -1 0 0 0 0 ;
0 -1 2 -1 0 0 0 ;
0 0 -1 2 -1 0 0 ;
0 0 0 -1 2 -1 0 ;
0 0 0 0 -1 2 -1 ;
0 0 0 0 0 -1 2 ] ;
[V D] = eig (A , B) ; for i=1:7
kappa(i) = D(i,i) ; % Eigenwerte end Kappamin = min(kappa) % Kleinster Eigenwert piMalKappamin = pi*Kappamin
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